Hey family,
I know that there are tests out there but I have been brushing up on my chemistry.
If you're using 99.98% pure potassium permanganate (KMnO4), you would need to calculate the amount required to oxidize the trenbolone enanthate present in 0.5 mL of a solution with a concentration of 150 mg/mL.
Here's how you can do the calculation:
1. **Determine the amount of trenbolone enanthate in the sample**:
- The sample contains 0.5 mL of a solution with a concentration of 150 mg/mL.
- So, the total amount of trenbolone enanthate in the sample is:
(0.5 ×150mg) = 75mg
2. **Calculate the stoichiometry of the oxidation reaction**:
- The oxidation reaction between trenbolone enanthate and potassium permanganate may not have a simple stoichiometry and may involve multiple steps.
3. **Estimate the amount of potassium permanganate needed**:
we'll approximate the amount of potassium permanganate needed based on the assumption of a one-to-one stoichiometry. This may not be accurate but can provide a rough estimate.
- If we assume a one-to-one stoichiometry, then the amount of potassium permanganate needed would be approximately equal to the amount of trenbolone enanthate present in the sample.
4. **Calculate the amount of potassium permanganate**:
- Since we're assuming a one-to-one stoichiometry, the amount of potassium permanganate needed would be approximately 75 mg.
Anyone used potassium permanganate or chromic acid to test their gear at home and save money on commercial tests?
I am curious on if anyone has experience and it seems like a good way to save money.
I know that there are tests out there but I have been brushing up on my chemistry.
If you're using 99.98% pure potassium permanganate (KMnO4), you would need to calculate the amount required to oxidize the trenbolone enanthate present in 0.5 mL of a solution with a concentration of 150 mg/mL.
Here's how you can do the calculation:
1. **Determine the amount of trenbolone enanthate in the sample**:
- The sample contains 0.5 mL of a solution with a concentration of 150 mg/mL.
- So, the total amount of trenbolone enanthate in the sample is:
(0.5 ×150mg) = 75mg
2. **Calculate the stoichiometry of the oxidation reaction**:
- The oxidation reaction between trenbolone enanthate and potassium permanganate may not have a simple stoichiometry and may involve multiple steps.
3. **Estimate the amount of potassium permanganate needed**:
we'll approximate the amount of potassium permanganate needed based on the assumption of a one-to-one stoichiometry. This may not be accurate but can provide a rough estimate.
- If we assume a one-to-one stoichiometry, then the amount of potassium permanganate needed would be approximately equal to the amount of trenbolone enanthate present in the sample.
4. **Calculate the amount of potassium permanganate**:
- Since we're assuming a one-to-one stoichiometry, the amount of potassium permanganate needed would be approximately 75 mg.
Anyone used potassium permanganate or chromic acid to test their gear at home and save money on commercial tests?
I am curious on if anyone has experience and it seems like a good way to save money.
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